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The soundtrack for ONE, an object show created by Cheesy Hfj. 

I know there are tracks from ONE already on SoundCloud but I couldn't find them compiled, so here.

Schleichen - ONE Original Soundtrack

Spow - ONE Original Soundtrack

FNF VS V - tan OST Sage

OG SONG: https://www.youtube.com/watch?v=sDN9iG0OOZA

if u want this down just leave a comment

FNF: Indie Cross - Sansational (Sans Song)

Music video:https://youtu.be/9w7Tu9SzBDc

Cover by:https://youtube.com/c/TJ255

FNF - Bloodshed but every turn a different cover is used

Left Unchecked  - Hypno's Lullaby - FNF

LYRICS:
You can't believe that you're still here
But I assure: fret not, don't fear
You're lost to time
You just keep counting, waiting

For the chance I come back
Another day we'd spend
Although your hope diminishes
You wish to see me again

And as it all just drones
As you lie there all alone
You listen for my voice
Although I'm quite not there

And as the record stands
Defeated at my own bare hands
Your mind is on the brink
But don't let these visions sink you

We can't heal every wound
So let it bleed
You want me back
I want you home
But is it really what we need?


You just can't let me go
You need to see
Sometimes you can't get what you want
So cut the link between
You and me

--

https://www.youtube.com/watch?v=rFF2hcosRtc 
Original by "Allenimations" 
The Nightly Manor by "Allenimations"

Between You And Me - TNM

Fnf Vs. Mickey Mouse Wednesday's Infidelity Reupload (Unknown Suffering/Song3)

Evaluate the line integral where C is the given curve. We're integrating over the curve C, y to the third ds, and C is the curve with parametric equations x = t cubed, y = t. We're going from t = 0 to t = 2. So we're going to integrate over that curve C of y to the third ds. We're going to convert everything into our parameter t in terms of our parameter t. So I'm going to be integrating from t = 0 to t = 2. Those will be my limits of integration. Now y is equal to t, so I'm going to replace y with what it's equal to in terms of t. So I'm going to be integrating the function t to the third. Now ds we're going to write as a square root of dx dt squared + dy dt squared, squared of all that as we said dt. So we're integrating now everything with respect to t. So this is going to be equal to the integral from 0 to 2 of t to the third times the square root of -- see the derivative of x with respect to t is 3 t squared. So we have 3 t squared squared + dy dt; well, that's just 1 squared dt. So we have the integral from 0 to 2 of t to the third times the square root of 9 t to the fourth + 1 dt. So this is a pretty straightforward integration here. We're going to let u be equal to 9 t to the fourth + 1 then du is equal to 36 t to the third dt and so that tells me I can replace a t to the third dt with a du over 36. And so we're going to have the integral then from -- well, new limits of integration. I'm just going to put some squiggly marks there to remind myself that we switched variables. So I'm not going from t = 0 to t = 2. I'm doing things in terms of you right now. But I have a 1 over 36. I'll put that out front, and we're going to have the square root of u. So u to the 1/2, t to the third dt was replaced by du over 36. We got the 36 out front. And so now this is a pretty easy antiderivative in terms of u. It's u to the 3/2 times 2/3. And again, different limits of integration. We could figure out what they are in terms of u, but I'm going to convert back into t. So we're going to have 1 over 36 times 2/3 times u to the 3/2. Now, u is 9 t to the fourth + 1, that to the 3/2 power. And now we can go ahead and go from original limits of integration 0 to 2. So let's see, when I put a 2 in here, we're going to have -- 1 over 36 times 2/3. That's going to be 1 over 54, isn't it? So we'll have 1 over 54 times -- putting a 2 in, we have 9 times 2 to the fourth. That's 9 times 16, which is 144 + 1, is 145. So we put the 2 in there, we get 145 to the 3/2 minus, putting the 0 in, we get 9 x 0 to the fourth. That's 0. 0 + 1 is 1. So we just get 1 to the 3/2 or 1. So let's see, what's the best way to write this. How about 1 over 54 -- I guess we could leave it like that. We could also write 145 to the 3/2 as 145 times the square root of 145 and then minus 1. And that is that line integral of y to the third ds over the given curve C.
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